Integrand size = 31, antiderivative size = 495 \[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\frac {\left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^3 e (3+m+2 p) (5+m+2 p) (7+m+2 p)}-\frac {(a B d (5+m)-b (4 B c+A d (7+m+2 p))) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^2 e (5+m+2 p) (7+m+2 p)}+\frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}-\frac {(b c (3+m+2 p) (2 b c (2+p) (a B (1+m)-A b (7+m+2 p))+(b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p)))-a (1+m) (2 b c d (2+p) (a B (1+m)-A b (7+m+2 p))+d (b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p))+2 (b c-a d) (a B d (5+m)-b (4 B c+A d (7+m+2 p))))) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-p,\frac {3+m}{2},-\frac {b x^2}{a}\right )}{b^3 e (1+m) (3+m+2 p) (5+m+2 p) (7+m+2 p)} \]
[Out]
Time = 0.49 (sec) , antiderivative size = 464, normalized size of antiderivative = 0.94, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.129, Rules used = {595, 470, 372, 371} \[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=-\frac {(e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {m+1}{2},-p,\frac {m+3}{2},-\frac {b x^2}{a}\right ) \left (\frac {a \left (a^2 B d^2 \left (m^2+8 m+15\right )-a b d \left (A d (m+3) (m+2 p+7)+B c \left (m^2+2 m (p+6)+2 p+27\right )\right )+b^2 c \left (A d (m+2 p+7)^2+8 B c\right )\right )}{b (m+2 p+3)}+c \left ((b c-a d) (a B (m+5)-A b (m+2 p+7))+\frac {2 b c (p+2) (a B (m+1)-A b (m+2 p+7))}{m+1}\right )\right )}{b^2 e (m+2 p+5) (m+2 p+7)}+\frac {(e x)^{m+1} \left (a+b x^2\right )^{p+1} \left (a^2 B d^2 \left (m^2+8 m+15\right )-a b d \left (A d (m+3) (m+2 p+7)+B c \left (m^2+2 m (p+6)+2 p+27\right )\right )+b^2 c \left (A d (m+2 p+7)^2+8 B c\right )\right )}{b^3 e (m+2 p+3) (m+2 p+5) (m+2 p+7)}+\frac {\left (c+d x^2\right ) (e x)^{m+1} \left (a+b x^2\right )^{p+1} (-a B d (m+5)+A b d (m+2 p+7)+4 b B c)}{b^2 e (m+2 p+5) (m+2 p+7)}+\frac {B \left (c+d x^2\right )^2 (e x)^{m+1} \left (a+b x^2\right )^{p+1}}{b e (m+2 p+7)} \]
[In]
[Out]
Rule 371
Rule 372
Rule 470
Rule 595
Rubi steps \begin{align*} \text {integral}& = \frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}+\frac {\int (e x)^m \left (a+b x^2\right )^p \left (c+d x^2\right ) \left (-c (a B (1+m)-A b (7+m+2 p))+(4 b B c-a B d (5+m)+A b d (7+m+2 p)) x^2\right ) \, dx}{b (7+m+2 p)} \\ & = \frac {(4 b B c-a B d (5+m)+A b d (7+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^2 e (5+m+2 p) (7+m+2 p)}+\frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}+\frac {\int (e x)^m \left (a+b x^2\right )^p \left (-c (2 b c (2+p) (a B (1+m)-A b (7+m+2 p))+(b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p)))-(2 b c d (2+p) (a B (1+m)-A b (7+m+2 p))+d (b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p))-2 (b c-a d) (4 b B c-a B d (5+m)+A b d (7+m+2 p))) x^2\right ) \, dx}{b^2 (5+m+2 p) (7+m+2 p)} \\ & = \frac {\left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^3 e (3+m+2 p) (5+m+2 p) (7+m+2 p)}+\frac {(4 b B c-a B d (5+m)+A b d (7+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^2 e (5+m+2 p) (7+m+2 p)}+\frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}-\frac {\left (c (2 b c (2+p) (a B (1+m)-A b (7+m+2 p))+(b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p)))+\frac {a (1+m) \left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right )}{b (3+m+2 p)}\right ) \int (e x)^m \left (a+b x^2\right )^p \, dx}{b^2 (5+m+2 p) (7+m+2 p)} \\ & = \frac {\left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^3 e (3+m+2 p) (5+m+2 p) (7+m+2 p)}+\frac {(4 b B c-a B d (5+m)+A b d (7+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^2 e (5+m+2 p) (7+m+2 p)}+\frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}-\frac {\left (\left (c (2 b c (2+p) (a B (1+m)-A b (7+m+2 p))+(b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p)))+\frac {a (1+m) \left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right )}{b (3+m+2 p)}\right ) \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p}\right ) \int (e x)^m \left (1+\frac {b x^2}{a}\right )^p \, dx}{b^2 (5+m+2 p) (7+m+2 p)} \\ & = \frac {\left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right ) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^3 e (3+m+2 p) (5+m+2 p) (7+m+2 p)}+\frac {(4 b B c-a B d (5+m)+A b d (7+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )}{b^2 e (5+m+2 p) (7+m+2 p)}+\frac {B (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (c+d x^2\right )^2}{b e (7+m+2 p)}-\frac {\left (c (2 b c (2+p) (a B (1+m)-A b (7+m+2 p))+(b c-a d) (1+m) (a B (5+m)-A b (7+m+2 p)))+\frac {a (1+m) \left (a^2 B d^2 \left (15+8 m+m^2\right )+b^2 c \left (8 B c+A d (7+m+2 p)^2\right )-a b d \left (A d (3+m) (7+m+2 p)+B c \left (27+m^2+2 p+2 m (6+p)\right )\right )\right )}{b (3+m+2 p)}\right ) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \, _2F_1\left (\frac {1+m}{2},-p;\frac {3+m}{2};-\frac {b x^2}{a}\right )}{b^2 e (1+m) (5+m+2 p) (7+m+2 p)} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 198, normalized size of antiderivative = 0.40 \[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=x (e x)^m \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \left (\frac {A c^2 \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-p,\frac {3+m}{2},-\frac {b x^2}{a}\right )}{1+m}+\frac {c (B c+2 A d) x^2 \operatorname {Hypergeometric2F1}\left (\frac {3+m}{2},-p,\frac {5+m}{2},-\frac {b x^2}{a}\right )}{3+m}+d x^4 \left (\frac {(2 B c+A d) \operatorname {Hypergeometric2F1}\left (\frac {5+m}{2},-p,\frac {7+m}{2},-\frac {b x^2}{a}\right )}{5+m}+\frac {B d x^2 \operatorname {Hypergeometric2F1}\left (\frac {7+m}{2},-p,\frac {9+m}{2},-\frac {b x^2}{a}\right )}{7+m}\right )\right ) \]
[In]
[Out]
\[\int \left (e x \right )^{m} \left (b \,x^{2}+a \right )^{p} \left (x^{2} B +A \right ) \left (d \,x^{2}+c \right )^{2}d x\]
[In]
[Out]
\[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\int { {\left (B x^{2} + A\right )} {\left (d x^{2} + c\right )}^{2} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\int { {\left (B x^{2} + A\right )} {\left (d x^{2} + c\right )}^{2} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m} \,d x } \]
[In]
[Out]
\[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\int { {\left (B x^{2} + A\right )} {\left (d x^{2} + c\right )}^{2} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right )^2 \, dx=\int \left (B\,x^2+A\right )\,{\left (e\,x\right )}^m\,{\left (b\,x^2+a\right )}^p\,{\left (d\,x^2+c\right )}^2 \,d x \]
[In]
[Out]